H=t^2+3t^2

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Solution for H=t^2+3t^2 equation: 



=H^2+3H^2

We move all terms to the left:

-(H^2+3H^2)=0

We get rid of parentheses

-H^2-3H^2=0

We add all the numbers together, and all the variables

-4H^2=0

a = -4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-4)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$H=\frac{-b}{2a}=\frac{0}{-8}=0$

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